[tex] \sqrt{5x-2}\ \textless \ 4 [/tex]

[tex] \sqrt{5x-2}\ \textless \ 4 [/tex]
- Предмет:
  Алгебра
- Автор:
  rapunzellu3b
- 5 лет назад

Ответы 1

Решение: $\sqrt{5x - 2} \ \textless \ 4$ $\left \{ {{5x- 2 \ \textless \ 16} \atop {5x- 2 \geq 0}} ight.$ $0 \leq 5x- 2 \ \textless \ 16 \\ 0+ 2 \leq 5x \ \textless \ 16 + 2 \\ 2 \leq 5x \ \textless \ 18$ $2: 5 \leq x \ \textless \ 18 : 5 \\ 0,4 \leq x \ \textless \ 3,6$ х ∈ [0,4; 3,6)Ответ: [0,4; 3,6)
- Автор:
  marquisedickson
- 5 лет назад
- 0
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[tex] \sqrt{5x-2}\ \textless \ 4 [/tex]

Ответы 1

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