найти сумму корней sqrt2x-1 =x-2

2x - 1 = (x - 2)^2

2x - 1 = x^2 - 4x + 4

x^2 - 4x + 4 - 2x + 1 = 0

x^2 - 6x + 5 = 0

D = 36 - 20 = 16

x1 = (6 + 4)/2 = 10/2 = 5

x2 = (6 - 4)/2 = 2/2 = 1

Проверка

√(10 - 1) = 5 - 2

√9 = 3

3 = 3

√(2*1 - 1) ≠ - 1

1 ≠ - 1

Ответ

5