Решите уравнение:
[tex] log_{2} ^{2} ( \alpha ) + 2 log_{2}( \alpha ) - 3 = 0[/tex]

log(2)α=t

t^2+2t-3=0; D=4+12=16

t1=(-2+4)/2=1; log(2)α=1; α1=2^1=2

t2=(-2-4)/2=-3; log(2)α=-3; α2=2^(-3)=1/8