(3x+2)(4x-1)-12=x решите срочно пж

(3x+2)(4x-1)-12=x

12x²-3x+8x-2-12-x=0

12x²+4x-14=0

6x²+2x-7=0

D= 4+168=172

x1= (-2+2√43)/12= (-1+√43)/6

x2= (-2-2√43)/12= (-1-√43)/6