найдите значение [tex]\sqrt{48*27}[/tex]

f '(x) = 2(3x2 + 5) + 6x(2x - 1). = 6x2 ... f'(x) = (x - 4)(20x + 11) - (5x - 2)(2x + 3)/(x - 4)2. = (20x2 +11x - 80x -44 - 10x2 -15x + 4x + 6)/(x - 4)2.