помогите решить:3[tex]x^{3} - x^{2} - 6x = 0[/tex]

помогите решить:3
[tex]x^{3} - x^{2} - 6x = 0[/tex]
- Предмет:
  Алгебра
- Автор:
  carsensih9
- 6 лет назад

Ответы 2

x³-x²-6x=0 ⇒ x(x²-x-6)=0 ⇒ x=0 U x²-x-6=0 (D=1+24=5², x1=(1-5)/2=-2, x2=(1+5)/2=3) ⇒ x=0 U x=-2 U x=3
- Автор:
  perry
- 6 лет назад
- 0
${x}^{3} - {x}^{2} - 6x = 0$ вынесем х: $x( {x}^{2} - x - 6) = 0$ x = 0; или ${x}^{2} - x - 6 = 0$ найдем корни: $d = {b}^{2} - 4ac = 1 - 4 \times 1 \times ( - 6) = 25$ $x1 = \frac{ - b + \sqrt{d} }{2a} = \frac{1 + 5}{2} = 3$ $x1 = \frac{ - b - \sqrt{d} }{2a} = \frac{1 - 5}{2} = - 2$ ответ : х= 0; х = 3; х = -2.
- Автор:
  pilarbaldwin
- 6 лет назад
- 0
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помогите решить:3[tex]x^{3} - x^{2} - 6x = 0[/tex]

Ответы 2

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помогите решить:3
[tex]x^{3} - x^{2} - 6x = 0[/tex]