в) (х-1)^2+(х-2)^2<1
г) (х+3)(х-2)>3х+10-(х+2)^2

в) (x-1)^2+(x-2)^2<1x^2-2x+1+x^2-4x+4<1x^2-2x+x^2-4x+4<12x^2-6+4<1 (разделим обе части уравнения на 2)x^2-3x+2<0x^2-x-2x+2<0x*(x-1)-2*(x-1)<0(x-1)*(x-2)<0{x-1<0 x-2>0{x<1 x>2 {x>1 x<2 x∈ (1;2)г) (x+3)*(x-2)>3x+10-(x+2)^2x^2-2x+3x-6>3x+10-(x^2+4x+4)x^2-2x-6>10-x^2-4x-4x^2-2x-6>6-x^2-4xx^2-2x-6-6+x^2+4x>02x^2+2x-12>0x^2+x-6>0x^2+3x-2x-6>0x*(x+3)-2*(x+3)>0(x+3)*(x+2)>0{x+3>0 x-2>0 {x+3<0 x+2<0{x>-3 x>2 { x<-3 x<2 x∈(-∞;-3)u(2;+∞)