1
[tex]2 \sqrt{128} - \sqrt{72} [/tex]
2.
[tex](3 \sqrt{2} + \sqrt{50} ) \times \sqrt{2} [/tex]
3.
[tex](6 - \sqrt{3} ) \times \sqrt{2} [/tex]

!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2√128 -√72 =2*√(2*64) - √(2*36)=2*8√2- 6√2=16√2-6√2= 10√2

(3√2+√50)*√2 = (3√2+√(2*25))*√2= (3√2+5√2)*√2=8√2 *√2=16

(6 - √3)*√2= 6√2- √6