6а^2+19а-1
__________
1-25а^2

(6a²+19a-1)/(1-25a²)=(a+3,22)(6a-0,3)/(1-5a)(1+5a)1-25a²=(1-5a)(1+5a)6a²+19a-1=6(a-(-3,22))(a-0,05)=(a+3,22)(6a-0,3)D=(-19)²-4×6×(-1)=361+24=385a1=(-19-√385)/2×6=(-19-19,6)/12=-38,6/12=-3,218~-3,22a2=(-19+√385)/2×6=(-19+19,6)/12=0,6/12=0,05