Решите уравнение : а) -8 (11-2а) + 40 = 3 (5а-4) б) 7 (-3 ( m-2)-m)-12=4 (5-3m)-4

-8(11-2a)+40=3(5a-4)-88-16a+40=15a-12-16a+15a=-12+48-1a=36a=36÷(-1)a=-367(-3(m-2)-m)-12=4(5-3m)-47(-3m+6-m)-12=20-12m-47(-4m+6)-12=16-12m-28m+42-12=16-12m-28m+12m=16-30-16m=-14m=14/16m=7/8