Решите тригонометрическое уравнение: Sin5x-sin3x=cos4x

sin5x - sin3x = cos4x2*sin[(5x - 3x)/2]*cos[(5x + 3x)/2] = cos4x2sinx*cos4x = cos4x2sinx*cos4x - cos4x = 0cos4x(2sinx - 1) = 0cos4x = 0 или 2sinx - 1 = 0cos4x = 0 или sinx = 1/24x = π/2 + πn, n ∈ Z; x = (-1)ⁿπ/6 + πn, n ∈ Zx = π/8 + πn/4, n ∈ Z; (-1)ⁿπ/6 + πn, n ∈ Zответ: x = π/8 + πn/4; (-1)ⁿπ/6 + πn, n ∈ Z.