cos (2pi-2x)+3sin (pi-x)=2

cos(2П-2x)+3sin(П-x)=2cos2x + 3sinx = 21 - 2sin²x + 3sinx - 2 = 02sin²x - 3sinx + 1 = 0sinx = t2t² - 3t + 1 = 0D = 9 - 4*2*1 = 1t₁ = (3 - 1)/4t₁ = 1/2t₂ = (3 + 1)/4t₂ = 11)  sinx = 1/2x = (-1)^n *arcsin(1/2) + πk, k∈Zx₁ =  (-1)^n* (π/6) + πk, k∈Z2)  sinx = 1x₂ = π/2 + πn, n∈ZПодробнее - на Znanija.com - https://znanija.com/task/15498403#readmore