Решите уравнение[tex]\sqrt{x+2}[/tex]=3x-4

(✓х+2)^2=(3х-4)^2х+2=9х^2-24х+16х+2-9х^2+24х-16=09х^2-25х+14=0D=25^2-4×9×14=625-504=121✓D=11x1=(25+11)/18x2=(25-11)/18x1=2x2=7/9Проверка:✓2+2=3×2-4✓7/9+2=3×7/9-42=27/2≠-7/2Ответ: 2