Решить уравнение (2x+3)^2-(x-5)^2=0

(2x+3)²-(х-5)²=04х² + 12х + 9 - х² + 10х - 25 = 03х²+22х -16=0D = 484 - 4×3×(-16)= √676= 26x1 = -22+26/2×3= 4/6 = 2/3x2 = -22-26/2×3 = -48 / 6 = -8