[tex]tgx=-\frac{4}{3}, \frac{3\pi }{2}\ \textless \ x\ \textless \ 2\pi [/tex]

Найти: [tex]cos\frac{x}{2}, sin\frac{x}{2}, tg\frac{x}{2}, ctg\frac{x}{2}[/tex]

tgx=-4/3;3π/2<x<2πtgx/2;cosx/2;sinx/2;ctgx/2=??1)1+tg²x=1/cos²xcos²x=1/(1+tg²x)=1/(1+16/9)=9/25cosx=+√9/25=3/52)3π/2<x<2π3π/4<x/2<π 3)sin²x/2=(1-cosx)/2=(1-3/5)/2=2/5*1/2=1/5sinx/2=+√(1/5)=√5/54)cos²x/2=(1+cosx)/2=(1+3/5)/2=8/5*1/2=4/5cosx/2=-√(4/5)=-2√5/55)tg²x/2=(1-cosx)/(1+cosx)=(1-3/5)/(1+3/5)=2/5/8/5=2/5*5/8=1/4tgx/2=-√(1/4)=-1/26)ctg²x/2=(1+cosx)/(1-cosx)=(1+3/5)/(1-3/5)=8/5*5/2=4ctgx/2=-√4=-2