Реши уравнение (3x-1)^2+(4x+2)^2=(5x-1)•(5x+1)

(3x-1)²+(4x+2)²=(5x-1)•(5x+1)

(3x-1)²+(4x+2)² - (5x-1)•(5x+1) = 0

9x²-6x+1 + 16x²+16x+4 - (25x²-1) = 0

25x²+10x+5 - 25x²+1 = 0

10x = - 6

x = - 6 : 10

x = - 0,6