y=x(квадрат)
x-3y=-3

1)xy+x-3y-3=0x-3+y(x-3)=0y(x-3)=3-xy=(3-x):(x-3) (2) x^2 + ((3-x):(x-3))^2=10(x^2(x-3)^2+(3-x)^2):(x-3)^2=0((x^2-1)(x-3)^2):(x-3)^2 =0x^2-1=0x^2=1x=-1, x=1 y^2=10-1y^2=9y= -3, y=3 Ответ - (-1;3) (-1;-3) (1;3) (1;-3)