Сократите дробь x2-x-6/x2-3x-10

1)x^2 - x - 6D = 1 + 4 * 6 = 25x1 = (1 + 5) / 2 = 3x2 = (1 - 5) / 2 = -2x^2 - x - 6 = (x - 3)(x + 2)x^2 - 3x - 10 D = 9 + 40 = 49x1 = (3 + 7) / 2 = 5x2 = (3 - 7) / 2 = -2x^2 - 3x - 10 = (x - 5)(x + 2)Сокращаем на х + 2( х не равно 2), получаем (х-3)/(х-5)

1)x^2 - x - 6

D = 1 + 4 * 6 = 25

x1 = (1 + 5) / 2 = 3

x2 = (1 - 5) / 2 = -2

x^2 - x - 6 = (x - 3)(x + 2)

x^2 - 3x - 10 

D = 9 + 40 = 49

x1 = (3 + 7) / 2 = 5

x2 = (3 - 7) / 2 = -2

x^2 - 3x - 10 = (x - 5)(x + 2)

Сокращаем на х + 2( х не равно 2), получаем (х-3)/(х-5)

как то так