Решите 14у+2у(6-у)=16у.6у

14у+2у(6-у)=16у*6у;

14y+12y-2y^2=96y^2;

26y-2y^2=96^2; ( делим обе части на 2 )

13y-y^2=48y^2;

13y-y^2-48y^2=0 ;

13y-49y^2=0;

y=0

или

13-49y=0;

13=49y;

y=13/49;

Ответ : y1=0 , y2=13/49

               

14y + 2y (6-y) = 16y,6y7y + y * (6-y) = 4,8y^27y + 6y - y^2 = 24/5 y^213y-y^2 = 24/5 y^265y - 5y^2 = 24y^265y - 5y^2 - 24y^2 = 065y - 29y^2 = 0y*(65-29y) = 0y=065-29y=0y=0y= 65/29y1=0y2=65/29