Уравнение
[tex]sin^{2}x-2=sin2x-cos^{2}x[/tex]

sin²x - 2 = sin2x - cos²xsin²x + cos²x - 2 = sin2x1 - 2 = sin2xsin2x = - 12x = (-π/2) + 2πnx = (-π/4) + πn , n ∈ ZОТВЕТ: (-π/4) + πn , n ∈ Z