Help pls
[tex] log_{x}(2) - log_{4}(x) + \frac{7}{6} = 0[/tex]
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log(x)2-log(4)x+7/6=01)x>0;x≠12)1/log(2)x-1/2*log(2)x+7/6=0log(2)x=t(1/t)-t/2+7/6=06-3t²+7t=03t²-7t-6=0D=49+72=121=11²t=(7±11)/6t1=3;t2=-4/6=-2/3log(2)x=3x=2³=8log(2)x=-2/3x=(1/2)²/³