x²y³-xy+y-y³ помогите пожалуйста

(x^2y^3 - y^3) - xy + y = y^3( x^2 - 1) - y( x - 1) = y^3(x - 1)(x + 1) - y(x - 1) =

= ( x - 1)(xy^3 + y^3 - y) = y( x - 1)(xy^2 + y^2 - 1)

x²y³-xy+y-y³ = y³(x-1)(x+1)-y(x-1) = y(x-1)(y²(x+1)-1)

Ответ : x²y³-xy+y-y³ = y(x-1)(y²(x+1)-1) .