log2(x^2-5x+8)=1x^2-5x+8>0D=25-32<0 всегдаx^2-5x+8=2x^2-5x+6=0x1=2x2=3---------------------lg 2^16 = log 0.5 (x+1) + 2x>-1lg 2 ^16 - lg 10^2 = log1/2 (x+1) lg (2^16/10^2)= log1/2 (x+1)x= (1/2)^lg(2^16/10^2) - 1----------------------------------log 3^x - log 3^(x^2-6) =0log 3^x = log 3^(x^2-6)x^2-x-6=0D=1+24=25x12=(1+-5)/2=3 -2x1=-2x2=3НАДЕЮСЬ ПРАВИЛЬНО