Решите уравнения:
1)
[tex]2x {}^{2} - 5 = 0[/tex]
2)
[tex] - x {}^{2} + 3 = [/tex]
3)
[tex](x + 1) {}^{2} - 4 = 0[/tex]
4)
[tex] - (x - 2) {}^{2} + 1 = 0[/tex]
5)
[tex] - 3(x + 3) {}^{2} + 48 = 0[/tex]
6)
[tex] \frac{4}{9} x {}^{2} - 1 = 0[/tex]
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1)2x²-5=0

2x²=5

x²=5/2

x²=2.5

x1=√2,5

x2=-√2.5

2)-x²+3=0

-x²=-3 *(-1)

x²=3

x1=√3

x2=-√3

3) (x+1)²-4=0

x²+2x+1²-4=0

x²+2x-3=0

Д=4-4*1*(-3)=4+12=16

x1=\frac{-b+√Д}{2a} =\frac{-2+√16}{2*1}=\frac{-2+4}{2}=\frac{2}2}=1

x2=\frac{-b-√Д}{2a} =\frac{-2-√16}{2*1}=\frac{-2-4}{2}=\frac{-6}2}=-3