1) √3cosx-sin2x=0
2) sinx-cos2x=-√2

√3cosx-sin2x=0√3cosx-2sinxcosx=0cosx(√3-2sinx)=01)cosx=0x=π/2+πk:k€Z2)√3-2sinx=0sinx=√3/2x=(-1)ⁿπ/3+πn;n€Zsinx-cos2x=-√2sinx-cos²x+sin²x=-√22sin²x+sinx-1+√2=0sinx=t2t²+t-1+√2=0D=1-8(-1+√2)=1+8-8√2=9-8√2<0t€∅;=>x€∅