Упростите и найдите значение алгебраической дроби

2)((3c-2d)(3c+2d))/(6cd(3c-2d))=(3c+2d)/(6cd)=(3×(5/3)+2×(1/2))/(6×(5/3)×(1/2))= (5+1)/5=6/53)(6x(x+2y))/(5y×(x+2y))=6x/5y=(6×(2/3))/5×(-2/5)= 4/-2=-24)(x+3y)^2/(4x(x+3y))=(x+3y)/4x= ((-2/10)+3(-6/10))/4(-2/10)=5/2