sin^2(p-x) + cos(p/2+x)=0​

sin²(π - x) + cos(π/2 + x) = 0sin²x - sinx = 0sinx•(sinx - 1) = 01) sinx = 0 ⇔ x = πn, n ∈ Z2) sinx = 1 ⇔ x = π/2 + 2πk, k ∈ ZОТВЕТ: πn, n ∈ Z ; π/2 + 2πk, k ∈ Z