[tex](x + 4 {)}^{2} = 3x + 40[/tex]
[tex]3(x + 4 {)}^{2} = 10x + 32[/tex]
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( х + 4 )² = 3х + 40

х² + 8х + 16 = 3х + 40

х² + 8х + 16 - 3х - 40 = 0

х² + 5х - 24 = 0

D = 25 - 4 × 1 × (-24) = 121 > 0. 11.

х1 = (-5 + 11) / 2 = 6/2 = 3.

х2 = ( -5 - 11) / 2 = -16/2 = -8.

Ответ : -8 ; 3.

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3 ( х + 4 )² = 10х + 32

3 ( х² + 8х + 16 ) = 10х + 32

3х² + 24х + 48 = 10х + 32

3х² + 24х + 48 - 10х - 32 = 0

3х² + 14х + 16 = 0

D = 196 - 4 × 3 × 16 = 4 > 0. 2.

х1 = ( -14 + 2 ) / 6 = -12/6 = -2.

х2 = ( -14 - 2 ) / 6 = -16/6 = -8/3 = -2 ⅔.

Ответ : -2 ; -2 ⅔.

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