Помогите решить логорифм

5^log3 90 * 5^(-log3 10) = 5^log3 90 * 5^log3 0,1= 5 ^(log3 90 + log3 0,1)=5^log3 9= 5^2= 25

log3(90) = log3(9) + log3(10) = 2 + log3(10)Получаем:5^[ log3(90) ] * (1/5)^[ log3(10) ] == 5^[ 2 + log3(10) ] * (1/5)^[ log3(10) ] == 5² * 5^[ log3(90) ] / 5^[ log3(90) ] == 5² = 25