Помогите с алгеброй пожалуйста, заранее спасибо

___ log27 11 = 1\log11 27 = 1/3*log11 3___ log3 11 = 1/log11 3___ log11 (5x+3V(x+1)+3)^3 = 3* log11 (5x+3V(x+1)+3)=>log27 11\log3 11 = log11 3 / 3*log11 3 = 1/3 log11 (3x+2V(x+1)+2) / 3*log11 (5x+3V(x+1)+3) >= 1\3log11 (3x+2V(x+1)+2) / log11 (5x+3V(x+1)+3) >= 1log11 (3x+2V(x+1)+2) >= log11 (5x+3V(x+1)+3)(3x+2V(x+1)+2) >= (5x+3V(x+1)+3)2x + V(x+1) + 1 =< 0 V(x+1) = t -----> (x+1) = t^2 -----> x = t^2-12*(t^2-1) + t + 1 =< 0Дальше легко