Алгебра. Решите уравнение.
Фото прикреплено.

log3(2-13/(x+5))^5=log3(1+13/(2x-3))-log3(2)log3(2x-3/x+5)^5=log3(2x+10/2x-3)-log3(2)5log3(2x-3/x+5)=log3(2(x+5)/2x-3)-log3(2)Замена: 2x-3/x+5 = y5log3(y) = log3(2/y) - log3(2)5log3(y) = log3(2) - log3(y) - log3(2)5log3(y) + log3(y) = 06 log3(y) = 0log3(y) = 0y = 3° = 1(2x-3) / (x+5) = 12x-3 = x+5x = 8