1-2sin² ^+cos²^ помогите плиииз ​

Ответ:

The expression 1-2sin²+cos² can be simplified using the identity cos²θ + sin²θ = 1:

1 - 2sin²θ + cos²θ = cos²θ + (1 - cos²θ) - 2sin²θ

= 1 - sin²θ - cos²θ - 2sin²θ

= 1 - sin²θ - (1 - sin²θ)

= 2sin²θ - 1

Therefore, 1-2sin²+cos² is equivalent to 2sin²θ - 1.