найти пределы функций:1) lim(2x³+x²+2/3x³+x-1) x--82) lim(3x³+x²+3/4x³+x-2) x--83) lim(x²-5x+6/x-2) x--2​

1) lim(2x³+x²+2/3x³+x-1) x--8

First, we can factor out the common terms in the numerator and denominator:

lim(2x³+x²+2 - (3x³+x-1)) / (3x³+x-1) as x approaches -8

lim((2x³+x²+2 - 3x³-x+1) / (3x³+x-1)) as x approaches -8

Now, we can simplify the expression:

lim((-x³+2x²+3) / (3x³+x-1)) as x approaches -8

As x approaches -8, the limit becomes:

lim((-(-8)³+2(-8)²+3) / (3(-8)³+(-8)-1))

= ((-512+2(64)+3) / (-512+(-8)-1))

= ((-512+128+3) / (-505))

= (-383