Алгебра я класс срочно

уже бегу....

Только
получается херня какая то.

To solve the quadratic equation 12x^2 + 39x - 16 = 0, we can use the quadratic formula, which is given by:


x = (-b ±√(b^2 - 4ac))/(2a)


Here, a = 12, b = 39, and c = -16. Substituting these values into the formula, we get:


x = (-39 ±√(39^2 - 4 · 12 · (-16)))/(2 · 12)


Now, let's simplify the expression:


x = (-39 ±√(1521 + 768))/24



x = (-39 ±√2289)/24



x = (-39 ± 47.874)/24


Therefore, the solutions are:


x_1 = (-39 + 47.874)/24≈ 0.412



x_2 = (-39 - 47.874)/24≈ -2.029


So, the solutions to the equation 12x^2 + 39x - 16 = 0 are approximately x ≈ 0.412 and x ≈ -2.029.