6sin(2x-п/6)cos(3x+п/3)-3sin(5x+п/6) решите уравнение: sin(3п/2-х)cos4x= корень3/4- 1/2cos3x

6*sin(2*x-пи/6)*cos(3*x+пи/3)-3*sin(5*x+пи/6)

-(27^(1/2)*sin(5*x)+3*cos(5*x)+(9*sin(2*x)-27^(1/2)*cos(2*x))*sin(3*x)+(3*cos(2*x)-27^(1/2)*sin(2*x))*cos(3*x))/2

-3*cos(x)