sqrt(5x-4)+sqrt(2x-1)=(sqrt3x+1)

\sqrt{5x-4} + \sqrt{2x-1} = \sqrt{3x+1} 5x+4 + 2* \sqrt{(5x-4)(2x-1)} + 2x - 1 =3x+12* \sqrt{(5x-4)(2x-1)} = 6-4x4 (5x-4)(2x-1) = 36 - 48x + 16x²40x² - 20x - 32x + 16 - 36 + 48x - 16x² = 024x² - 4x - 20 = 06x² - x - 5 =06 - 1 -5=0x₁ = 1      x₂ = -5/6  не удов., т.к. 5x-1≥0Ответ: 1