• 1) log12 3 + log12 4
    2) log7 98 - log7 2
    3) log2 5 - log2 35 + log2 56
    4) log1/3 5 - log1/3 5 + log1/3 9
    помогите пожалуйста как сможете
    1) lg4 + lg250
    2) log2 6 - log2 6/32
    3) (log12 4 + log12 36)^2
    4) lg13 - lg130
    5) (log2 13 - log2 52)^5
    6) (log0,3 9 - 2log0,3 10)^4
      Решите уравнение 
    1) log3 x = -1
    2) log2 x = -5
    3) log3 x = 2
    4) log4 x = 3
    5) log4 x = -3
    6) log7 x = 0
    7) log1/7 x = 1
    8) log1/2 x = -3
      Вычислите
    1) log2 log2 log3 81
    2) log2 log3 log1/3 1/27
    3) log√3 log5 125
    4) log4 log3 81
      как сможете помогите пожалуйста срочно заранее спасибо


Ответы 1

  • 1) log₁₂3 + log₁₂4 = log₁₂(3*4) = log₁₂12 = 12) log₇98 - log₇2 = log₇(98/2) = log₇49 = 23) log₂5-log₂35 + log₂56 = log₂(5/35) + log₂56 = log₂( \frac{5*56}{35})= log₂8 = 34) log₁/₃5 - log₁/₃5 + log₁/₃ 9 = log₁/₃9 = -21) lg4 + lg250= lg(4*250) = lg1000 = 32) log₂6 - log₂ \frac{6}{32} = log₂( \frac{6*32}{6}) = log₂32 = 53) (log₁₂4 + log₁₂36)² = (log₁₂144)² = 2² = 44) lg13 - lg 130 = lg \frac{13}{130} = lg \frac{1}{10} = -15) (log₂13-log₂52)⁵ = (log₂ \frac{13}{52} )⁵ = (log₂ \frac{1}{4} )⁵ = (-2)⁵ = -326) (log₀.₃9 - 2log₀.₃10)⁴ = (log₀.₃9 - log₀.₃100)⁴ = (log₀.₃ \frac{9}{100} )⁴ = (log₀.₃0.09)⁴ = 2⁴ = 161) log₃x = -1x = 3⁻¹ = 1/32) log₂x = -5x = 2⁻⁵ = 1/323) log₃x = 2x = 3² = 94) log₄x = 3x = 4³ = 645) log₄x = -3x = 4⁻³ = 1/646) log₇x = 0x = 7° = 17) log₁/₇x = 1x = 1/78) log₁/₂x = -3x = (1/2)⁻³ = 81) log₂log₂log₃81 = log₂log₂4 = log₂2 = 12) log₂log₃log₁/₃(1/27) = log₂log₃3 = log₂1 = 03)  log_{ \sqrt{3} } log₅125 =  log_{ \sqrt{3} } 3 = 24) log₄log₃81 = log₄4 = 1
    • Автор:

      truffles
    • 6 лет назад
    • 0
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