log(4x+5) по основанию 5 =2+log(x-4) по основаю 5

спасиииибо)

log(4x+5) = 2 + log(x-4) => log(4x + 5) - log(x - 4) = 2=> log((4x + 5) / (x - 4)) = 2=> (4x + 5) / (x - 4) = 25=> 4x + 5 = 25x - 100=> 21x = 105=> x = 5