log по основанию 5 (x+1) log по основанию 5 (x-3) =1   решите уравнение плиииииззз

log(5x-3)-log(x-1)=1 ----(1)log[(5x-3)/(x-1)]=1     log(a)-log(b) = log(a/b)[(5x-3)/(x-1)]= (10)^1 [(5x-3)/(x-1)]= (10)(5x-3)=10X(x-1)5x-3 = 10x-10-3+10 = 10x-5x7 = 5x5x =7x = 7/5