найдите разность 
[tex] \frac{1}{5x}- \frac{-11x+y}{5xy} [/tex]

\frac{1}{5x} - \frac{-11x+y}{5xy} = \frac{y}{5xy} - \frac{-11x+y}{5xy} = \frac{y-(-11x+y)}{5xy} = \frac{y+11x-y)}{5xy} = \frac{11x}{5xy} =\frac{11}{5y}