помогите решить

4sin^2x -5sinxcosx - 6cos^x=0

4sin²x -5sinxcosx - 6cos²x=0|:cos²x≠04tg²x-5tgx-6=0 |t=tgx4t²-5t-6=0D=(-5)²-4*4*(-6)=25+96=121=11²t1=(5+11)/8=2                      t2=(5-11)/8=-0,75tgx=2                                     tgx=-0,75x=arctg2+πn, n∈Z                x=-arctg0,75+πn, n∈Z