Помогите решить
[tex]1- sinx+cosx=0[/tex]

cosx - sinx + 1 = 0cos(2*x/2) = cos^2(x/2) - sin^2(x/2)sin(2*x/2) = 2sin(x/2)*cos(x/2)1 = cos^2(x/2) + sin^2(x/2)cos^2(x/2) - sin^2(x/2) - 2sin(x/2)*cos(x/2) + cos^2(x/2) + sin^2(x/2) = 02cos^2(x/2) - 2sin(x/2)*cos(x/2) = 02cos(x/2)*(cos(x/2) - sin(x/2)) = 01) cos(x/2) = 0x/2 = π/2 + πkx = π + 2πk2) cos(x/2) - sin(x/2) = 0sin(x/2) = cos(x/2)tg(x/2) = 1x/2 = π/4 + πkx = π/2 + 2πk