1)x∈(-≈;-5)(x+1)/(x+5)=(x+1)/(x-5)(x+1)(x-5)-(x+1)(x+5)=0(x+1)(x-5-x-5)=0-10(x+1)=0x=-1∉(-≈;-5)2)x∈[-5;-1](x+1)/(x+5)=(x+1)/(5-x)(x+1)(5-x)-(x+1)(x+5)=0(x+1)(5-x-x-5)=0-2x(x+1)=0x=0∉[-5;-1]3)x∈(-1;≈)(x+1)/(x+5)=(x+1)/(x-5)(x+1)(x-5)-(x+1)(x+5)=0(x+1)(x-5-x-5)=0-10(x+1)=0x=-1∉(-1;≈)ответ х=-1