решите неравенство 14x-2>(2x-1)(x+5)
Предмет:
АлгебраАвтор:
epifaníaptf7Задание:
решите неравенство 14x-2>(2x-1)(x+5)
Решение:
Откроем скобки в правой части :
2х^{2}+10x-x-5
2х^{2}+9x-5
Перенесем левую часть в правую :
14x-2-2х^{2}-9x+5=0
Упрощаем :
-2х^{2}+5x+3=0 Умножим обе части на (-1) :
2х^{2}-5х-3=0
Решим по Дискриминанту :
D=25+24=49
x1=5-7/4=-0/5
x2=5+7/4=3
Автор:
mikeymacias14х-2>2х^2+9x-5
перенесём всё влево
2x^2-5x-3<0
2x^2-5x-3=0
D=25+24=49=7^2
x1,2=(5+-7)/4=-1/2;3
2(x+1/2)(x-3)<0
Отмечаем точки на числовой прямой проводим линию и бах http://clip2net.com/s/1YX6V х принадлежит от -1/2 не включая до 3 не включая
Автор:
dollyaw8dДобавить свой ответ
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