решите уравнение сos (х+П/6)=-1/2

сos (х+П/6)=-1/2x+π/6=2π/3+2πn       x+π/6=-2π/3+2πnx=2π/3-π/6+2πn        x=-2π/3-π/6+2πnx=π/2+2πn                x=-5π/6+2πn

сos (х+П/6)=-1/2х+π/6=+- (π-π/6)+2πn, n∈Zx+π/6=+-5π/6 +2πn, n∈Zx=+-5π/6 - π/6 +2πn, n∈Zx1=5π/6-π/6+2πn, n∈Z            x2=-5π/6-π/6+2πn, n∈Zx1=2π/3+2πn, n∈Z                   x2=-π+2πn, n∈Z