1)x≤10(10-x)/(x²-3x-2)≥(10-x)/(x²-4x-5)(10-x)(x²-4x-5-x²+3x+2)/(x²-3x-2)(x²-4x-5)≥0(10-x)(-x-3)/(x²-3x-2)(x²-4x-5)≥010-x=0⇒x=10-x-3=0⇒x=-3x²-3x-2=0⇒D=9+8=17⇒x1=(3-√17)/2 U x2=(3+√17)/2x²-4x-5-0⇒x1+x2=4 U x1*x2=-5⇒x1=-1 U x2=5 + _ + _ + _ +________________________________________________________________________ -3 -1 (3-√17)/2 (3+√17)/2 5 10x∈(-≈;-3] U (-1;(3-√17)/2) U ((3+√17)/2;;5) U x=102)x>10(x-10)/(x²-3x-2)≥(10-x)/(x²-4x-5)(x-10)(x²-4x-5-x²+3x+2)/(x²-3x-2)(x²-4x-5)≥0(x-10)(-x-3)/(x²-3x-2)(x²-4x-5)≥0x-10=0⇒x=10-x-3=0⇒x=-3x²-3x-2=0⇒D=9+8=17⇒x1=(3-√17)/2 U x2=(3+√17)/2x²-4x-5-0⇒x1+x2=4 U x1*x2=-5⇒x1=-1 U x2=5 _ + _ + _ + _______________________________________________________________________ -3 -1 (3-√17)/2 (3+√17)/2 5 10Решения на промежутке (10;≈) нет