Cosx+корень из 3 * sinx=2

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формулаа*cos+b*sinx=2√(a²+b²)=√(1+3)=22sin(x+arcsin1/2)=2 |:2sinx(x+π/6)=1x+π/6=π/2+2πk, k € Zx=π/6+2πk, k € ZОтвет: π/6+2πk.