Решите уравение:1/x - 10/x^2-5x = x-3/5-x

(1/X ) - (10/X^2 - 5X) = X - 3 / 5 - X X - 5 - 10 = - X * ( X - 3 ) -------------------------------------X ≠ 0 X ≠ 5 ----------------------------------X - 15 = - X^2 + 3X X^2 + X - 3X - 15 = 0 X^2 - 2X - 15 = 0 D = 4 + 60 = 64 ; √ D = 8 X1 = ( 2 + 8 ) : 2 = 5 X2 = ( 2 - 8) : 2 = ( - 3 ) -------------------------------- Ответ Х = ( - 3 )