y(max) + y(min) - ?
y=(2sin3x + 2cos3x)^2

y=(2sin3x+2cos3x)^2y=(2*√2*(√2/2 *sin3x+√2/2* cos3x)^2=8*sin^2(3x+π/4)      0 <=sin^2 (3x+π/4)<=1         0<=y<=8ymax+ymin=0+8=8Ответ:8