решите уравнение:√3х - 5= 3-√2х

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√(3х - 5)= 3-√2х√(3х - 5) + √2x = 3ОДЗ 3x - 5 >=0x >=1 2/33x + 2x - 5 + 2√(2x(3x - 5)) = 92√(6x^2 -10x) = 14 - 5x√(6x^2 -10x) = 7 - 2.5x6x^2 - 10x = (7 - 2.5x)^26x^2 - 10x + 35x - 49 - 6.25x^2 = 0-0.25x^2 + 25x - 49 = 00.25x^2 - 25x + 49 = 0D = 25*25 - 4*0.25*49 = 576x1 = (25 + 24)/0.5 = 98x2 = (25 - 24)/0.5 = 1/0.5 = 2